0=64q^2-25

Solution for 0=64q^2-25 equation:

0=64q^2-25

We move all terms to the left:

0-(64q^2-25)=0

We add all the numbers together, and all the variables

-(64q^2-25)=0

We get rid of parentheses

-64q^2+25=0

a = -64; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·(-64)·25
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*-64}=\frac{-80}{-128}
=5/8
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*-64}=\frac{80}{-128}
=-5/8
$